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Full Version: Some difficult add math questions...
Innovating
Logarithms

Given:
loga xy3 = m
loga x3 y2 = n
Express loga (xy)1/2



loga xy3 = loga am
xy3 = am
x = am / y3 --------- 1

loga x3 y2 = n
x3 y2 = an
x3 = an / y2
x = (an / y2) 1/3 --------- 2

am / y3 = (an / y2) 1/3
a3m / y9 = an / y2
a3m / an = y9 / y2
y7 = a3m-n
y = (a3m-n)1/7

x = am / y3
x = am / [(a3m-n)1/7]3
x7 = a7m / a9m-3n
x7 = a7m-9m+3n
x7 = a3n-2m
x = (a3n-2m)1/7

loga(xy)1/2
= logax1/2y1/2
= 1/2 logax + 1/2 logay
= 1/2 loga(a3n-2m)1/7 + 1/2 loga(a3m-n)1/7
= 1/14 logaa3n-2m + 1/14 logaa3m-n
= 1/14 (3n-2m+3m-n)
= 1/14 (2n+m)

*SOLVED*
Level: High
Colour
you use replacement method didn't you , okay standard for me but still sort of high standard
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